AOD

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Pl gv solution

#Mathematics #Calculus #Applications of Differentiation

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2 Answers

1357

Manish Shankar ·2014-06-08 09:23:10

t=0, V=V₁

t=5, V=2V₁/3

t=10, V=V₂

c=lnV₁

so we have

ln(V/V₁)=-kt

ln(2/3)=-5k

ln(V2/V1)=-10k

ln(V2/V1)=2*ln(2/3)=ln(4/9)

V2/V1=4/9

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1357

Manish Shankar ·2014-06-06 22:57:28

\frac{dV}{dt}=-kV \Rightarrow \frac{dV}{V}=-kdt \Rightarrow lnV=-kt+c

Proceed from here

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Sahil Jain please solve it. I am not geeting the answer
Upvote·0· Reply ·2014-06-08 07:57:29
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Basic Integral Calculus Operators Symbols Matrix Cases

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