1but point B .. how is it (1,-2) ?
Asish Mahapatra B lies on C1, so satisfies y=x[p]2[/p]-3
and as B : (1,y2), y2 = 1-3 = -2Upvote·0· Reply ·2013-06-25 00:03:23- Subhradeep Patra ya.. got it... thanx
Two curves C1 : y = x2 - 3 and C2 : y = kx2, k ε R intersect each other at two different points. The tangent drawn to C2 at one of the points of intersection A(a,y1), (a>0) meets C1 again at B (1, y2) (y1 ≠y2). The value of 'a' is
(A) 4
(B) 3
(C) 2
(D) 1
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2 Answers
1357B=(1,-2)
y1=ka2
Equation of line
y-y1x-a=2ka
it passes through B
So -2-ka2=(1-a)2ka
ka2-2ka-2=0
Also we have a2=3/(1-k)
1