23area of sector OAB = r2θ2 = 14πr2
area of Δ AOB = r22
area common between Semicircle and circle = 14Ï€r2 - r22
area of semicircle = 12 Ï€ (r√2)2 = 14Ï€r2
area of semicircular part outside circle = 14Ï€r2 - ( 14Ï€r2 - r22)= r22
hence ratio = 1
In a circle with center O , OA , OB r radii angle AOB = 90 degrees . A semi circle (S1) is constructed using segment AB as its diameter non - overlapping with triangle OAB . The ratio of the area of S1 outside given circle to the area of triangle OAB is equal to
(A) 1/2
(B) pi/4
(C) 1
(D) none of these
plzzzz give the full soln........
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3 Answers
23
6hmmmm
found a little difficult to visualise it but turned out to be pretty straight forward in the end
thnx qwerty!!:)
