The area bounded by mod(2x+y) + mod(x-2y) ≤4
[where mod→modulus]
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1 Answers
1when both \left|2x+y \right| & \left|x-2y \right| is +ve then the line becums 3x-y≤4...
When \left|2x+y \right| is +ve but \left|x-2y \right| is -ve then line becums x+3y≤4...
when \left|2x+y \right| is -ve but \left|x-2y \right| is +ve then line becums -x-3y≤4...
when both \left|2x+y \right| & \left|x-2y \right| is -ve then the line becums -3x+y≤4...
solve get the point of intersection by drawing the lines and find the reqd area of a the quad..
atleast i think this is the way to solve this 1 :P
