11pls... some one help me with this sum...
A point P moves inside a triangle formed by A(0,0), B(1,1/√3), C(2,0) such that min{PA,PB,PC} =1, then the area bounded by the curve traced by P is....
(a) 3√3 - 3∩/2.
(b) √3 + ∩/2.
(c) √3 - ∩/2.
(d) 3√3 + 3∩/2.
i am nt getting the meaning of min{PA,PB,PC} = 1 IN THE SUM...
PLS... SOLVE THIS...
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7 Answers
33b should be (1,√3)
what that means is distance of P from A B or C can be minimum of 1 i.e. none of PA PB or PC should be less than 1 i.e. point P can't lie inside circles of radius 1 centered at A B or C
so P lies inside the triangle and outside the 3 circles
so req area= area of triangle - are of three sectors (i.e. half circle since 60°+60°+60°)
√3-Π/2
1there is no point such that {PA,PB,PC} is 1...
it must be sqrt(3) not 1/3
1Whos answer is correct. according to me it is wrong.. there must be sum correction needed for this particular queston