1it can b rearranged to [-(cosx/4-1)2+5/4]
its eql to 1 for x=0,120,180,240,360 deg.
Find the area bounded by the curves x2+y2=4, y=x2+x+1,
y=[sin2(x/4)+cos(x/4)] and the x-axis,where [.] denotes greatest integer function!!
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44 Answers
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62it can b rearranged to [-(cosx/4-1)2+5/4]
what about when cos x=-1??
ie when x=180 degree
check for that agian
62but u need to worry about a lot of points that u havve not found anything dear...
I was only pointing that this solution u are giving has mistakes.. find them ...
1ll d area bounded b equal 2 area bounded by d circle wit x axi???????????????????????????????? plz don scold........
1cheak dis for 3rd curve
btw 0-120 deg
1. value of cosx/4 willl be +ve
2.max val will be .8660 for which curv =1
3. for other val in btw cosx/4 ->1 so cosx/4-1 -->0 hence curve will be 1
*** othr values chkd by log table (sry)
1acc to me make green line horizontal passing through y=1 for x=-120 to120
then the required area will be quite obvious
1i think its equal 2 d area bounded by d circle................
