area....

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If the area enclosed between x²+y²â‰¤9(pi)² and sin(x-y)â‰¥0 is m(pi)³n sq units,then find [m]-[n]+[m+nm-n]?

#Mathematics #Calculus

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man111 singh ·Feb 23 '13 at 9:55

$\hspace{-16}$Now from Graph We have seen that the area of shaded region is \\\\\\ Half of Total Area of the Circle. So Shaded area is.........\\\\\\ $\bf{=\frac{1}{2}.\pi.9\pi^2=\frac{9\pi^3}{2}}$\\\\\\ So after Camparing , We Get $\bf{m=9}$ and $\bf{n=2}$\\\\\\ So $\bf{[m]-[n]+\left\[\frac{m+n}{m-n}\right\]=9-2+\left\[\frac{9+2}{9-2}\right\]=7+1=8}$$

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