106
Asish Mahapatra
·2010-12-20 17:38:17
yes it is correct.
\int_{0}^{\frac{\pi}{2}}{\frac{dx}{1+cos^2x}} \equiv \int_{0}^{\frac{\pi}{2}_{-}}{\frac{dx}{1+cos^2x}}
a single point of discontinuity/being infinite or not being defined doesnt affect the value of the integral. and hence it is perfectly fine to divide by cos^2x
1
swordfish
·2010-12-21 01:04:25
Yes it doesnot affect the value of the integral. But the method can be proved wrong mathematically ( method followed after dividing by cos2x )
According to Fundamental Theorem of Calculus, the integrand must be continuous on [a, b], which is what you do when you find an antiderivative for f and evaluate it at the two endpoints. Otherwise you are dealing with an improper integral. If f is not defined at the endpoints (or at points inside the interval), you must use limits to evaluate the integral which the author doesn't mention/use.