1wts the probability
1. What is probability that axx+bx+c=0 has
a.real roots
b. roots in (1,2)
2. What is condition that axx+bx+c=0 has
a. roots in (1,2)
b. has roots in (8055,8055.55)
-
UP 0 DOWN 0 0 4
4 Answers
49roots = -b±√b2-4ac2a
the second question follows from there!!
also if u are well-conversant with interpreting an equation graphically then the 2 hands of graph must cut between (m,n) where m and n are the limits!! :)
cheers!!
39you canot take the probability as there are so many possibilities for it to have real roots
infinitely many
1for the prob. that it has real roots:-
when a,b,c are real,
it depends on the discriminant D=(b^2 -4ac)
4 cases:-
i) D=0 (real and equal roots)
ii) D>0, D=perfect square (real, rational and distinct roots)
iii) D>0, D≠parfect square (real, irrational and conjugate)
iv) D<0 (non real roots)
so, the probability is 3/4
i don't know if this is at all the correct solution.. please pardon me if i have done any mistakes