BITSAT 2

yup it is c but..my doubt is u get something like -sinx//sinx/...so how can u say it is -1 for sure?

why not none of these then....

yesss!!!
it shld be none of dese bcoz u r gettin smthin lik [-sinx/mod(sinx)]
so when we sinx 2 b +ve we hv answer 2 b (+1) && if sinx is -ve den d answer is (-1)

do u guys agree???

but i got -1 only.... [12]

y = sin^-1cos(x)
= sin^-1sin(Î /2 - x) [hope x is between 0 to pi ]

dy/dx = -1.

i think they didn take any limits into account.

here's a other look at this perspective
see it like

sin^-1(sin√1-x²)
=√1-x²
dy/dx= none of these
but #12 is perfect and so as mine

so the question is ambigious[1]

I am commenting on post #12,

according to sky sin^-1(sin(Î /2-x))=Ï€/2 - x....
but that is true for a certain limit of interval.. (as sky said "hope x is between 0 to pi") . so the q is really ambiguous