1ya
lim n→∞∫(1-t3/n)^n*t2.dt=2√2/3
limits of integral 3√-a and 3√ a
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5 Answers
62∫(1-t3/n)n x t2.dt
I=1/3 ∫(1-t3/n)n x 3t2.dt
t3=k
3I = ∫(1-k/n)n x dk
3I = -(1-k/n)n+1/(n+1) limit: -a to a
3I= (1+a/n)n+1 - (1 - a/n)n+1
Limit as n tends to infinity, this will become.. ea-e-a = 2 √2
so we will get ea=√2+√3
so a= ln( √2+√3 )
Is this the right answer?
1ya it s right but i did binomial expansion in d second last step wat s wrong in dat
62Could you tell me the second last step's meaning/
as long as you are not approximating there is nothing wrong with binomial expansion..
If after bnomial expansion, you are able to get back the sum in a "good form" then the method is perfect.