1ans.= 2
first integrate the given eq f'(x)=g'(x)+c
put x=1
u will get c=2
now it's f'(x)=g'(x)+2
integrate again now f(x)=g(x)+2x+c
put x=2
then c=-10
therefore f(x)-g(x)=2x-10 put x=4 and ans=2
if f(x) nd g(x) r twice differentiable functions on [0,2] nd if f''(x) = g''(x) nd f' (1) =4 , g' (1)=2 nd f(2)=3 , g(2)=9 then find g(4)- f(4)??
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2 Answers
1