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1. fundamental period of [x]+[2x]+[3x]+[4x]+[5x]-15x.....=
2. fndmntl prd of a*[sin*{b tan(x)}].........
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3 Answers
1357[x]+[2x]+[3x]+[4x]+[5x]-15x..... = -({x}+{2x}+{3x}+{4x}+{5x})
The fractional parts being periodic with periods 1, 1/2, 1/3, 1/4, 1/5 respectively..
So the period of this function would be the LCM* of These numbers which is 1.
13572nd one is again periodic with a period of pi..
Think of why? he period depends only on the part inside sin(...)