11im getting 3/2
( dont worry i may be wrong)
THE AREA ENCLOSED BETWEEN y2=x AND THE LINE x+y=2.
me getting 7/6+something/2
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13 Answers
1no worries !!
it was easier if one takes y-axis coordinates but i took x-coordinates
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1getting 9/2 ... by method of entire rotation of graph by 90°anticlock wise ...
now the equations are x2 = y and y - x = 2
u can check that the area between the two curve is same in my graph and the graph of the original equation
now we can simply write the equation of area as
∫from -1 to 2 {(2+x) - x2 dx}
→ 2x + x2/2 - x3/3
→ put limits
→ 6 + 4/2 - 1/2 - 8/3 - 1/3
→ 3 + 3 /2
→ 9 / 2
1well ankit... u tuk both d equations wronggg... so u ended up wid d correct answer...!!! :P
well, answer is 9/2... procedure is d same as ankit solved above... :)
P.S. : ankit... dun edit d posts to such a large extent... next 2-3 posts luk useless now...!!! dun repeat it buddy... :)
1@:-)& KR ... dude my both the equations are correct .. u haven't seen i have rotated the axes .. draw my graph and the original one .. u will see both enclose the same area ...
instead of the original equation i have written equivalent expressions ....
1kuch nahi yaar humko yeh method aasaan laga isi liye kiye .. ∫y dx humko jyada accha lagta hai ∫x dy se
