1function is continuous everywhere coz at integral point ,the nature of function has to be changed, bt at integral points function's value is0.dhanssu question hariya bhai.
f(x) = [x]cos(2x-12) pie , where [] is greatest integer is discontinuous at ??????????????
a) all x b) all integer points
c) no x d) x which is not an integer
e) at all I+ f) at all I-
g) at (n)pie h) at (n-1)pie
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4 Answers
1ans (c)
the function could have been discontinuous only due to [x] since 'cos' is continuous in R...
but at the points where [x] is discontinuous, i.e, integral points, makes the given function vanish (since cos (odd)Î 2=0), and thereby making it continuous!!
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