first of all u need to get the fn which is very simple in this case...by simple manipulation u getf(x) x-x2=k
=>f(x)=kx-x3
given f(1)=1
=>1=k-1 =>k=2
=>f(x)=2x-x3
now can u complete it ??
let f(x) be a differentiable function satisfying (x-y)f(x+y)-(x+y)f(x-y)= 4xy(x2-y2) for all x,y belongs to R . f(1) = 1 then....
1. the area of the region bounded by the curves y=f(x) and y=x2 is....
2. the value of ∫-12 f(x) dx is........
first of all u need to get the fn which is very simple in this case...by simple manipulation u getf(x) x-x2=k
=>f(x)=kx-x3
given f(1)=1
=>1=k-1 =>k=2
=>f(x)=2x-x3
now can u complete it ??
eure u hav done a mistake...after ur first step
2nd step bears d result f(x)=kx+x^3
at f(1)=1
k=0
therefore f(x)=x^3