1
Ricky
·2010-09-24 06:24:30
Obviously , the antiderivative of the given function ( which , in this case , turns out to be a
Hypergeometric series ) is not so easy to find . Also the integration must be carried out in a
manner in which convergence issues must be taken care of . But since here " n " is given to
be a natural number , so we need not worry about them . However a stricter condition
would have been ;
Real Part Of " n " > 1 .
I denote the original integral as " I " .
Now in the original integral , let us substitute



Here , I used two standard identities involving Gamma functions . The first one is -

which is nothing but ,

And the second one , commonly referred to as Euler ' s Reflection Formula is -

1
Ricky
·2010-09-24 06:30:42
Another thing that struck me while I pondered over the solution is that the usage of complex
integration , i . e , Contour Integration may have been an efficient way , but still , I think that would
require a high skill in Complex Analysis which I obviously lack .
6
AKHIL
·2010-09-24 06:40:04
is this thing in course of JEE??
23
qwerty
·2010-09-24 07:01:00
ricky tune fod diya yaar, ur posts look like as if prophet/kaymant sir are replying
tnx man
akhil ye sab syllabus me nai hai
1
sanchit
·2010-09-30 10:05:48
awesum got to noe abt tht Euler ' s Reflection Formula thnxx ricky bhaiiya