Definite Integration

If 0∫k 1/2+8x2 = Pi/16 then k=

Edit: It is whole by 2+8x2

3 Answers

62
Lokesh Verma ·

\int \frac{1}{1+4x^2}dx=1/2tan^{-1}(x/2)

So the given integral you have given is 1/4(tan-1(k/2) = pi/16

so tan-1(k/2) = pi/4

so ... k/2=1 so k=2

1
zzz ·

nishant bhaiyya

k= 1/2 naa???

1
zzz ·

\int \frac{1}{1+ 4x^2} =\frac{1}{2}\tan^{-1}(2x)

???

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