If 0∫k 1/2+8x2 = Pi/16 then k=
Edit: It is whole by 2+8x2
\int \frac{1}{1+4x^2}dx=1/2tan^{-1}(x/2)
So the given integral you have given is 1/4(tan-1(k/2) = pi/16
so tan-1(k/2) = pi/4
so ... k/2=1 so k=2
nishant bhaiyya
k= 1/2 naa???
\int \frac{1}{1+ 4x^2} =\frac{1}{2}\tan^{-1}(2x)
???
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