1.\int_{0}^{x}[1+t]^{3}dt
2.\int_{0}^{x}[x]dx
plz help sir
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2 Answers
13572.\int_{0}^{x}[x]dx=\int_{0}^{[x]}[x]dx+\int_{[x]}^{x}[x]dx=\int_{0}^{1}0dx+\int_{1}^{2}1dx+...+\int_{[x-1]}^{[x]}[x-1]dx+\int_{[x]}^{x}[x]dx=0+1+2+3+...[x-1]+[x](x-[x])
1357similarly you can try the first one
Aritra das roy thank you sir
Upvote·0· Reply ·2014-08-19 10:44:24