definite1

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saikat007 mukherjee ·2010-12-29 06:44:04

puting x=0 in the equation, we have,
0= 1 - c.1.[lim 0 to 1âˆ«f(t)e^-t dt]
or, lim 0 to 1 âˆ«f(t)e^-tdt=1c
now differentiating the equation,
f(x)= e^x - 2e^2x.c.1c
or, f(x)= e^x - 2e^2x
now, lim 0 to 1 âˆ«f(x)e^-xdx= lim 0 to 1 âˆ«(1 - 2e^x)dx = 3 - 2e
so c= 13-2e

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definite1

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