Derivaives(maxima minima)

rrom arihanr

2 Answers

Q1 the function :
f(x) = log(logx)logx

is increasing for x< e^e(almost equal to 10)
and decreasing for x > e^e

so for xâ‰¡(-âˆž,e^e)

f(x') < f(y') (where x' < y') --------(1)

and for xâ‰¡(e^e,âˆž)

f(x') > f(y') (where x' < y')-----------(2)

put x'=4 and y'=5 in 1st equation
and put x'=30 and y'=31 in 2nd equation

so answer is (b,c)

3) f(1) < f(x)

hence
-1 + b³-b²+b-1b²+3b+2 > 2(1) - 3

=> (b-1)(b²+1)(b+1)(b+2) >0

which gives

b\in (-2,-1)\bigcup{}(1,\propto )

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