Let Sin-1x = t.
We require d{(Sint)t}/dt
= (Sint)t (ln(Sint)) Cost
= (xSin-1x)(lnx)(√(1-x2))
1 Answers
metal
·2009-06-11 09:58:55
Let Sin-1x = t.
We require d{(Sint)t}/dt
= (Sint)t (ln(Sint)) Cost
= (xSin-1x)(lnx)(√(1-x2))