derivatives

y=sin(cos^-1(tan(sec^-1x)))
find dy/dx

1 Answers

ya,looking horrible i think. let me make it simpler

tan( sec^-1 x) = âˆš x² - 1 (its the whole root) u cn get it by converting sec^-1x into tan^-1x and then use tan( tan^-1t)= t, for all t belongs to R

now cos^-1(âˆš x²-1) = âˆš 2 - x² (same way as the previous)

so,y = âˆš 2 - x². now hpr u cn do the rest

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