3here x tends to 0
if f(x) be twice differentiable function and f''(0)=2 then find
limit of [2f(x)-3f(x)+f(x)]/x^2
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7 Answers
1The numerator is EXACT ZERO while the denominator tends to zero. Hence this is NOT indeterminate and hence the answer is zero
1limit x tends to 1, because numerator is zero and denominator is x^2 which is zero and this posssible only when x tends to 1 and not zero .
1@abhisek
ya ya..u r right.. i didnt see that numerator was always 0. srry :))
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