(y3-2x2y)dx + (2xy2 - x3)dy =0, then the value of xy√(y2-x2) is
1. y2 +x
2. xy2
3. any constant
4. none of these
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5 Answers
Lokesh Verma
·Sep 28 '09 at 7:43
take y = tx
you will get
now solve it :)
I hope i have not made any calculation error :P
rupal jain
·Sep 29 '09 at 0:39
my ans is ax2......a is a constant
but the ans to this ques is (c) any constant
Lokesh Verma
·Sep 29 '09 at 0:41
the question is given that =
the RHS is not clear.. can you make sure that the RHS is zero?
THat is why i din try it whole heartedly either !