differential equation

somebody please help!!!!

sin x dydx= 2y² cosxsinx + 2y cosx +2cosxsinx
sinxdy-ycosxdxsin²x=1sin²x[ 2y²cosxsinxdx+ycosxdx+2sinx cosxdx]
d[ysinx]= cosxsin²x[2y²dxsinx + ydx + 2sinx dx ]
d[ysinx]= 2cotx[ y²sin²x+ y2sinx+ 1]dx
d[ysinx]= 2cotx [(ysinx+14)²+ 1516]dx
put t= ysinx

∫ dt[(t+1/4)²+(√15/4)²= ∫ 2cot x dx

2√15tan^-1[4ysinx+1√15]= ln/sinx/ + c
where /./ is mod and c is a constant

theres an even shorter solution

take sinx=t

ull get it of homogenous nature then u can do watever is reqd.. (simple variable substitution)

btw surbhi's answer is correct