1
°ღ•๓ÑÏ…Î
·2008-11-19 06:59:47
m nt gettin ur q properly
is it that we hav 2 find d dif of {y3d2y/dx2}
u can try by P(x)=ax^2+bx+c
tehn find dy/dx then d2y/dx2 in this wer u get dy/dx susbtitue frm wat u hav found
then multiply by y^2 ..
then i dunno wat ur q says ....... if it says diff it thn go ahead
cheero~
62
Lokesh Verma
·2008-11-19 07:09:15
y3d2y/dx2
on doing this, u will get
P"(x)P(x)/2-P'(x)/4
" stands for double derivative
' stands for single derivative
so, 2.d/dx{y3d2y/dx2}
will be P'''(x).P(x)+{P"(x)}2-P"(x)/2
Dont know if i have made a stupid mistake.. i guess putting a,b,c,d will give a clearer picture :)