graph se to thik hai.. par thinking of algebraic....(i am working on weak points.. :P)
let F(x)=a∫xf(t)dt
F(x+λ)=a∫x+λf(t)dt
F(x+λ)=a∫xf(t)dt+x∫x+λf(t)dt
F(x+λ)=F(x)+x∫x+λf(t)dt
iske aage.. ??
If f(x)is be periodic with period λ & f(-x)+f(x) =0
Prove that ax∫f(t)dt is periodic with λ
graph se to thik hai.. par thinking of algebraic....(i am working on weak points.. :P)
let F(x)=a∫xf(t)dt
F(x+λ)=a∫x+λf(t)dt
F(x+λ)=a∫xf(t)dt+x∫x+λf(t)dt
F(x+λ)=F(x)+x∫x+λf(t)dt
iske aage.. ??
phew!!
The point was i wanted to solve this one widout any visualisataion of question... [3]
Good work philip..
I din wnat to give away everything isliye gave only this much away to priyam ;)
arre kya zarurat hai algebraic se karne ki
put
t= k + x + lamba /2
dt = dk
limits now bcome -λ/2 to λ/2 (hopefully [3])
and that is zero............... i wonder if u want to do that also algebraically (but even then its doable)
graph se to dikh hi raha hai.. ki x to x+λ zero hoga... but i haev decided to do it algebraiclly....... k=t-x acha dekhte hain...
-x se x tak zero.. hoga... lekin isse kya fayda...uske aage karne ke liye..
iske aage hi to nikaalna hai
good beginning but do end it with a good end[1]
i didnt thought that way
i will be glad to see some justification(theoretical or graphical)[1]
No it is not useless.. but now it should ring a bell in all your heads..
That is because if you can think of a graph .. lot of areas get cancelled to zero :P
sir we have to prove the obvious thing[1]
SIR IF U THINK THIS QUESTION IS USELESS THEN WE MAY LEAVE THIS QUESTION!!!!!!!!!!!
it was not mentioned in the question.............
that wont effect the ques
but abhi u should understand the motive of the ques!!!!!!!!!!!
SORRY GUYZ AND GALS
BUT BHOOK LAG RAHI THI [3]
I HOPE ITS COMPLETE NOW
NOW ITS CORECTED
that should have been understood
not a big matter it was
now focus.............
i hope its clear now!!!!!!!!!!!!!!!!!!!!
the 1st statement itself doest mak sense
kya angrezi likhi hai