do these relations always hold...?

1)f(xy)=f(x)+f(y) implies f(x)=klnx or f(x)=0
2)f(xy)=f(x).f(y) implies f(x)=x^n
3)f(x+y)=f(x).f(y) implies f(x)=a^kx
4)f(x+y)=f(x)=(fy) implies f(x)=k where k is a constant
and
5)f(x).f(1/x)=f(x)+f(1/x) implies f(x)=±x^n +1

6 Answers

1
sam X ·

the last one is well proved !
i know you have taken this extract from "differential calculus "---arihant !

62
Lokesh Verma ·

Arshad this is a good set of quesitons to prove...

THe last one was proved by Prophet sir here if i remember correctly...

The others are a good exercise.. (Dont learn these results directly!)

1
injun joe ·

The first three can also be proven. If you want, i'll let you know the proof...

66
kaymant ·

These statements are not true always. They require some additional constraints. The first four require the continuity of f at atleast one point or monotonocity. The last one require that f(x) be a polynomial.

1
Arshad ~Died~ ·

thank u sir...

62
Lokesh Verma ·

@arshad.. for polynomials these wil always hold.. (sorry i made that assumption :P)

but even otherwise try to prove these ...

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