double limit

\hspace{-16}\mathbf{\lim_{x\rightarrow 0}\left[\frac{(1+4x)^{\frac{1}{x}}}{e^4}\right]^{\frac{1}{x}}}

6 Answers

e^-8

i am getting âˆž <doesnt exsit>.

262

Aditya Bhutra ·2011-10-30 11:00:24

e^-8 is correct.

Am getting 1 as answer.

We know lim f(x)/g(x) is same as lim f(x)/lim g(x).

Now bring e^4/x in denominator and find the limits separately.

You will get lim { e^4/x/e^4/x} = 1 at the end.

1708

man111 singh ·2011-10-31 20:14:35

Yes answer=e^-8

well I think we have to apply 1^infinity type application

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