Doubt on Calculas

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A real valued function f is defined on the interval (-1,2).A point x is said to be a fixed point of f if f(x)=x.Suppose that f is a differentiable function such that f(0)>0 and f(1)=1.Show that if f'(1)>1,then f has a fixed point in the interval (0,1).

#Mathematics #Calculus

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Hardik Sheth ·2013-04-25 05:21:12

draw the graph...its easy..

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Rohit Chowdhuri ·2013-04-25 19:53:48

Can't figure out the procedure!Please give a suitable solution for it.

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Hardik Sheth since derivative at 1,greater than 1,slope is greater than the slope of y=x..nw since f(0)greater than 0,u have to cut the line y=x atlest once so that slope of tangent at x=1 is greater than 1
Upvote·0· Reply ·2013-04-25 23:12:49
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Basic Integral Calculus Operators Symbols Matrix Cases

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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Doubt on Calculas

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