y = √x + √y +y
=> √y = -√x => dy/2√y = -dx/2√x
=> dy/dx = -√y/√x = √x/√x = 1.
y = √x + √y +y
=> √y = -√x => dy/2√y = -dx/2√x
=> dy/dx = -√y/√x = √x/√x = 1.
y = √(x + √(y +y))
y = √(x + √2y)
y2= x + √2y
y4 - 2xy2 +x2 - 2y = 0
(4y3-4xy-2)dy/dx = 2y2-2x
Note: this question can have many more forms.. i mena that the answer can be given in many different equivalent expressions....
So you should try to see if there is a prove that kind of thing in this problem... so that we can prove it to that particular expression...
@akhil , arey! toh bracket dena tha naa!! (shit! ek asaan sa pink chala gaya [3])