dy/dx

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y=âˆšx+âˆšy+âˆšx+âˆšy+............to âˆž then dy/dx=

#Mathematics #Calculus

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6 Answers

1

skygirl ·2009-01-11 18:13:09

y = âˆšx + âˆšy +y

=> âˆšy = -âˆšx => dy/2âˆšy = -dx/2âˆšx

=> dy/dx = -âˆšy/âˆšx = âˆšx/âˆšx = 1.

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akhil mm ·2009-01-11 22:22:31

no sky,
wat i wrote is no a simple sq root but a whole sq root

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Ð”Ð²Ò¥Ñ—ÑuÏ now in medical c ·2009-01-11 22:38:02

y=√x+√y+y

Did u mean that?????

then it is simple

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kishan nageswaran ·2009-01-11 23:32:55

dy/dx=(2y+1)/4*(logy - y) is it correct

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Lokesh Verma ·2009-01-12 03:15:39

y = âˆš(x + âˆš(y +y))

y = âˆš(x + âˆš2y)

y²= x + √2y

y⁴ - 2xy² +x² - 2y = 0

(4y³-4xy-2)dy/dx = 2y²-2x

Note: this question can have many more forms.. i mena that the answer can be given in many different equivalent expressions....

So you should try to see if there is a prove that kind of thing in this problem... so that we can prove it to that particular expression...

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skygirl ·2009-01-16 18:52:55

@akhil , arey! toh bracket dena tha naa!! (shit! ek asaan sa pink chala gaya [3])

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