easssy integrations..

\int \frac{cos\: 2x-cos\:2\alpha }{cos\:x-cos\:\alpha }dx

1 Answers

cos(2x)-cos(2Î±)=2*(cos^2(x)-cos^2(Î±))

so given integral becomes 2(cos(x)+cos(Î±))

so answer is 2*sin(x)+2xcos(Î±)

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