easy one

VITEEE 2015 Papers › Calculus questions › easy one

#Mathematics #Calculus

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9 Answers

1

Aditya ·2009-03-12 05:16:18

b. by Newton-Leibnitz formula

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Aditya ·2009-03-12 05:19:06

f'(x)=-(e^-cos²xsinx+e^-sin²xcosx)

Putting pi/4,

f'(pi/4)=-√2/e

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1

Akand ·2009-03-12 05:27:07

dude isnt it -âˆš2/e?????

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Aditya ·2009-03-12 05:29:13

Thanks Akand.....corrected it.

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Sabitha Venkates ·2009-03-12 05:34:41

I think too its rite ans...
-âˆš2/e

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Akand ·2009-03-12 05:37:47

sabitha...........thts wrong.......d actual answer is -âˆš2/e.......not -âˆš2/e

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Aditya ·2009-03-12 05:40:35

Arey akand....its the same yaar....here the sq. root sign appears in this manner only....-√2/e...happy!

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Akand ·2009-03-12 05:41:23

dude adi...........i kno yaar.....time pass nahi ho raha tha thts all.........heheheheehehhe

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Aditya ·2009-03-12 05:41:55

And already i hav mentioned that the answer is b initially.

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω