Evaluation of Integral

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Find \int_0^1 (1-x^{2008})^{\frac{1}{2009}} dx - \int_0^1 (1-x^{2009})^{\frac{1}{2008}} dx

28 Answers

13
deepanshu001 agarwal ·

substitute( 1-x^a)^(1/b) = t

13
deepanshu001 agarwal ·

sry......

24
eureka123 ·

@ dipanjan, really awesome solution..........[1][1]........

1
Dipanjan Das ·

When we substitute something in place of x should we not change the limits too??
that's what has been done.

13
deepanshu001 agarwal ·

in 7 th last line limits of the second integral are 1 to 0 and then in the 3 rd last line they hav becum 0 to 1 without ny change in sign

1
Dipanjan Das ·

I can't see where you got that generalization.
that is not true.
But this one is:

btw also see that I have not flipped the limits. I have substituted something in place of ....hope you will get my point .

13
deepanshu001 agarwal ·

tapan can u plz ans my above post ....

21
tapanmast Vora ·

Lovely solution mate!!

OH K so v hav a generalization here :

∫f(x) + f-1(x) dx

xf-1(x)

EXPERTS PL. reply to this :

POST #10

13
deepanshu001 agarwal ·

i didnt get the third last step ....

limits flip ho gayi but where is the minus sign.....

341
Hari Shankar ·

jishnu can be recognized anywhere with his lucid posts. Good job bro

1
Dipanjan Das ·

the general form can be evaluated similarly.

13
deepanshu001 agarwal ·

integral xdx from 0 to 1 = integral tdt from 0 to 1...

hence after the above substitution v get the result....

1
KR ·

hmm..........thininkin.........[12]

thought of trying to take x 2009 out from one and x2008 from other but.............

21
tapanmast Vora ·

then wat deep

13
deepanshu001 agarwal ·

it luks as if the ans is 0....

21
tapanmast Vora ·

for the first integral :

I hav a feelin,
substitutin either 1-x2008 OR x2008 as sinθ cud b helpful

341
Hari Shankar ·

In general we will have\int_0^1 (1-x^a)^{\frac{1}{b}} dx = \int_0^1 (1-x^b)^{\frac{1}{a}} dx

13
deepanshu001 agarwal ·

sir will it b 0 for small constants like 1,2 or 3.... also

21
tapanmast Vora ·

OYE b555 kaise yaar, how is 2nd ODD re-chk brother

39
Dr.House ·

sry

21
tapanmast Vora ·

Sir,
Nothing is for sure, but going by the ODDS, is my following observation likely 2b true than false :

wenever in integration, power/number as big as 2008/09 cums I hav a feeling dat the solution to such a problem cud b arrived at by treating the no. as any arbitrary constant a,

Now observing the relation b/w the BIG constant and other equally big const. (if any)
A GENERAL equation can b formed and then very simple values like 1,2 can b substituted!!!

21
tapanmast Vora ·

VERY BAD METHOD : [2]


this integral can b written as : (1 - xa)1/a+1 - (1 - xa+1)1/a

NOW let a = 1;

u wud find I = 0,
this generalsition cud b disastrous!! LAST option if nothin strikes
but this is a very crude methd & I mite get a beating frm math lovers here....

341
Hari Shankar ·

Such problems will usually have a guessable answer. Here its ZERO

21
tapanmast Vora ·

ANS : 0 ?? [7]

21
tapanmast Vora ·

I m tryin to solv dis one in the normal fashion, but Sir can u pl. provide us wid OPTIONS, coz I had a slite keyhole in mind by which v can judge the crrct option!!!

13
deepanshu001 agarwal ·

the powers are so large .... and v hav 2 integrate only for numbers in 0 to 1....

24
eureka123 ·

one way.....apply by parts on first.......[12][12]

341
Hari Shankar ·

looks can be deceptive. Would you like to justify your answer

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