f(x)

given g(f(x))=x.then f(x) is one-one/onto/both/one one but not necessarily onto

2 Answers

think of inverses and the condn of inverse funtions.

g(f(x))=x

ie g(x)=f^-1(x)

since inverse of f(x) exists f(x) is both one-one and onto.

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