1 Answers
Asish Mahapatra
·2010-07-06 18:58:31
f(x+1) + f(x-1) = √2 f(x) .. (1)
so, √2 f(x+1) + √2 f(x-1) = 2 f(x)
=> [f(x+2) + f(x)] + [f(x) + f(x-2)] = 2f(x) [using (1) for f(x+1) and f(x-1)]
=> f(x+2) + f(x-2) = 0 .. (2)
=> f(x-2) + f(x-6) = 0 .. (3)
from (2) and (3),
f(x+2) = f(x-6)
=> f(x) = f(x+8)
so period = 8
calc. errors could be there