find the definite integral of

THis is

_3/4∫^9/25 dx/{(1-x)√x}

no no that is wrong.. i have to think.

keep aside the limits for now...

the integration is basically...I = dx/((1+√x)√x(√1-x))
so
take 1+√x=t.
=> dx/2√x=dt.
=> dx/√x=2dt.
then,
√(1-x)= √(2t-t²)
so the integration boils down to a std. form......

I= ∫2dt/ t√(2t-t²)
here, put t=1/z. and u can easily solve...
then put limits....