1@Kalyan..
-the denominator will be = 0 when x =0 only
- here (x-1)/(2[x]-x) >= 0...
so either x>=1 AND [x] >= x/2....[always true]
OR
x<=1 AND [x]<=x/2..[true when x<0 ]
So i feel it is (-∞,0) U [1,∞]
f(x)=√(x-1)/x-2{x}
Please post ur solutions
My ans (-∞,∞)-{0}
answer given :(-∞,0)union(0,1]union[2,∞)
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3 Answers
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6wel @jsgenius
i dnt kno d answer ...dis is a sum given by one of my frnds
from arihant
d answer given there was more weird one........