1Hmm dude... I think the qsn was
lim x->a F(x) = [x] sin (Î [x+1])
So in that case, u better use this method :
LHL = limx->a- F(x) = (x-1) sin(Î x-1 + 1)
= (x-1) sin ( Î x)
RHL = limx->a+ F(x) = (x) sin(Î x + 1)
= x sin (Î x + 1)
why have they used h---->1 for LHL and h----->0 for RHL??can u account for this!
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3 Answers
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