lim:x→0:- [3x.ln(sinx/x)2 + x3] [|x+1| + |x-1| - 2]x(x-sinx)(1-cosx)
- Aditya Agarwal options:
a) 0
b) 2
c) 4
d) 6Upvote·0· Reply ·2013-07-22 10:23:27
lim:t→x ( sinx-sintx-t) = f (sinx)
Find range of f(x)
(A) (-∞,1]
(B) [-1,0]
(C) [0,1]
(D) [-1,∞)
lim:x→0:- [3x.ln(sinx/x)2 + x3] [|x+1| + |x-1| - 2]x(x-sinx)(1-cosx)
For the first one,
cosx = f(sinx)
=> (1-x2)1/2 = f(x)
=> 0 ≤ f(x) ≤ 1
for the first one, i was also getting (a)
and 2nd one too, my answer was coming to be 0.