1708\hspace{-16}$Rewrite the expression as $\mathbf{f(x)=\frac{x+2}{x}}$\\\\\\ Now Replace $\mathbf{x\rightarrow f(x)\;,}$ We Get\\\\\\ $\mathbf{f(f(x))=f^2(x)=\frac{f(x)+2}{f(x)}=\frac{3x+2}{x+2}}$\\\\\\ Similarly $\mathbf{f(f(f(x)))=f^3(x)=\frac{3f(x)+2}{f(x)+2}=\frac{5x+6}{3x+2}}$\\\\\\ Similarly We Calculate $\mathbf{f^4(x)\;,f^5(x)\;,f^6(x)\;,.........}$\\\\\\ So here We have seen a pattern which is $\mathbf{f^{n}(x)=\frac{ax+b}{cx+d}}$\\\\ Where $\mathbf{c\neq 0}$\\\\ So after Solving The equation $\mathbf{f^{n}(x)=x\Leftrightarrow \frac{ax+b}{cx+d}=x}$\\\\ We Get Max. $\mathbf{2}$ Real Roots.\\\\ So In General The Given Equation has $\mathbf{2}$ Solution.\\\\ Now after certain Recursive iteration Fn. repeat itself\\\\\\
\hspace{-16}$(I dont Know after what time it will repeat Itself)\\\\ So The equation $\mathbf{f_{n}(x)=x\Leftrightarrow \frac{x+2}{x}=x}$\\\\$\mathbf{x^2-x-2=0\Leftrightarrow x=-1\;,2\;, n\geq 1}$
