33:D
so f(0)=0
and f'(x)=x2
therefore f(x)=x3/3
hehehe
putting it in original equation...
(x+y)3/3=x3/3+y3/3+x2y... they are not equal...
[3]
Let f be a differentiable function such that f(x+y)=f(x)+f(y)+x2y
and lim f(x) = 0
x→0 x
Then find f'(10)
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UP 0 DOWN 0 0 10
10 Answers
62f(x+h)-f(x)=f(h)+x2h
divide by h and take limit to zero
f'(x) = 0+x2
so f'(10) = 100
3362hmm.. half cooked question...
chalo good that you saw so far..
.. (btw)you missed a constant but that wont matter..
33[3]
f(x+h)-f(x) = x2h+xh2
h h h
here this term should have been there... but answer is not changed because it turns out to be zero..
then f(x)=x3/3
to iska matlab... koi f(x) nahi hoga kya... [7]
from partial derivative it doesnot give any function...
33so... in 1st principle derivative method... theres a fault.. [4]