its a constant function f(x) = 3!!!!!!!!!
so its even ......
y=f(x) is a function on R->Q and continuous such that f(2)=3.then the function is even/odd/increasing/cant be said.
there is a beautiful explanation by kaymant sir here http://targetiit.com/iit-jee-forum/posts/passage-tmh-11710.html
ya i sort of got that but in the solution its given f(x) is even coz f(x)=x2-1.why is this necessary??
debanjana..
If your question is "why is f(x) even" then teh answer is because f(x)=f(-x)
If your question is that "why is f(x) = x^2-1" then the answer is it is not.. because if f(x) is given by x^2-1 then it will have a point where it will take an irrational value. Which is not allowed.