d
- Ranadeep Roy Please post the solnUpvote·0· Reply ·2013-12-23 05:13:04
Let f(x+y)=f(x).f(y) and f(x)=1+sin(3x).g(x) where g(x) is cont. , then f'(x) is
a) f(x).g(0)
b)3g(0)
c) f(x).cos(3x)
d)3f(x).g(0)
e)3f(x).g(x)
d
f'(x) = lim (h->0) f(x+h) - f(x)h
= f(x)f(h) - f(x)h
=f(x)[f(h) - 1]h
=f(x)[sin(3h)g(h)]h
=f(x)[sin(3h)g(h)]3hx3
=3f(x)g(h)
=3f(x)g(0)