262f(x) = \begin{cases} 17/3 - x^{3} & \text{ if } x>1 \\ -1-x^{3}& \text{ if } x\in [-1,1] \\ -13/3 - x^{3}& \text{ if } x<-1 \end{cases}
\hspace{-16}\bf{\mathbb{F}}$ind a function $\bf{f:\mathbb{R}\rightarrow \mathbb{R}}$ that satisfy\\\\\\ $\bf{2f(x)+f(-x)=\left\{\begin{matrix} \bf{-x^3-3}\;\;\;,\;x\leq 1\\\\ \bf{7-x^3}\;\;\;,\;x> 1 \end{matrix}\right.}$
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3 Answers
1f(x) = 73-x3 ; x>1
= -x3-1 ; x≤1
consider x>1 and replace x→-x and solve both equations and similarly for x≤1
262
11lol..I am getting f(x) a constant function..
f(x)=17/3!!!
its it right?
