3not getting
6 Answers
62Hint: draw the graph
The slope will either be 1 or -1 other than at critical points...
Give it a shot
62what is the value of the function at x=-1, x=1, x=0
will there be another point where the shape of the graph changes?
1also,if we draw the sign scheme of f(x) we will find four intervals and their values would be:
f(x)= (x-1) when x belongs to (1,∞)
= -x+1 ,when x belongs to (0,1)
= x-1 ,when x belongs to (-1,0)
= -x-1 ,when x belongs to (-∞,-1)
sumeet, hope now u cn find f'(x) in d respective intervals
62One simpler method
Draw the graph of |x|
then Think of |x|-1
Then draw the graph of ||x|-1|
Then it is trivial :)