(1+\tan^2 x)^2-4\tan^3 x + 4 \tan x = \tan^4 x -4 \tan^3 x + 2 \tan^2 x + 4 \tan x +1
=(\tan^2 x -2 \tan x -1)^2 \ge 0
So (4) is the right option
The expression wherever defined, sec4x - 4tan3x+ 4tanx is always :
1. positive
2. negative
3. non- positive
4. non negative
i think it shud be +ve........
find its derivative
it is an inc funcn i think!!
(1+\tan^2 x)^2-4\tan^3 x + 4 \tan x = \tan^4 x -4 \tan^3 x + 2 \tan^2 x + 4 \tan x +1
=(\tan^2 x -2 \tan x -1)^2 \ge 0
So (4) is the right option