functions...ATGS

hey subho.....
just check out this link 4 da solution......

http://www.targetiit.com/iit-jee-forum/posts/differentiation-2-17388.html

i had also asked the same doubt earlier.....

f(a)=Ï€
x=Ï€2

f'(Ï€2)=3

now use

f^{-1}(f(x))=x \\ \frac{d }{d x}{f^{-1}(f(x))}=1\\ \texttt{apply chain rule} \\ \frac{d }{d x}{f^{-1}(f(a))}=\frac{1}{f'(a)}

\frac{d }{d x}{f^{-1}(\pi)}=\frac{1}{3}