max[sin(x)] = 1;
eqtn bcums
(x-pi)(2pi-x)
then u can solv it bcums easy then
How many integers are in the domain f(x) = ln(3Ï€x-x2-2Ï€2-sinx)
A)4
B)3
C)5
D)2
max[sin(x)] = 1;
eqtn bcums
(x-pi)(2pi-x)
then u can solv it bcums easy then
ya now im also getting 3.....der was a mistake.....while solving.....now i got it thanks sky....[1][1][1]..